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0=-0.31x^2+0.19x
We move all terms to the left:
0-(-0.31x^2+0.19x)=0
We add all the numbers together, and all the variables
-(-0.31x^2+0.19x)=0
We get rid of parentheses
0.31x^2-0.19x=0
a = 0.31; b = -0.19; c = 0;
Δ = b2-4ac
Δ = -0.192-4·0.31·0
Δ = 0.0361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.19)-\sqrt{0.0361}}{2*0.31}=\frac{0.19-\sqrt{0.0361}}{0.62} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.19)+\sqrt{0.0361}}{2*0.31}=\frac{0.19+\sqrt{0.0361}}{0.62} $
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